(5x+1)^(1/2)+(x+3)^(1/2)=4

Simple and best practice solution for (5x+1)^(1/2)+(x+3)^(1/2)=4 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Solution for (5x+1)^(1/2)+(x+3)^(1/2)=4 equation: 



(5x+1)^(1/2)+(x+3)^(1/2)=4

We move all terms to the left:

(5x+1)^(1/2)+(x+3)^(1/2)-(4)=0

We add all the numbers together, and all the variables

(5x+1)^(+1/2)+(x+3)^(+1/2)-4=0

We multiply all the terms by the denominator


(5x+1)^(+1+(x+3)^(+1-4*2)=0



We calculate terms in parentheses: +(5x+1)^(+1+(x+3)^(+1-4*2), so:

5x+1)^(+1+(x+3)^(+1-4*2

determiningTheFunctionDomain
5x+(x+3)^(+1-4*2+1+1)^(

We add all the numbers together, and all the variables

5x+(x+3)^(-5)^(

Back to the equation:

+(5x+(x+3)^(-5)^()





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





We calculate terms in parentheses: +(5x+(x+3)^(-5)^(), so:

5x+(x+3)^(-5)^(





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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